Replace Array Value with Array Value

Question

I want to replace a template of data $Arraytest with actual data from an XML file Arraytest2.

So I to replace the $Arraytest.Values with those from $Arraytest2.Values and save them for further process.

$Arraytest = @{
    TLC     = 'TLC'
    Crew3LC = 'Crew3LC'
    MyText  = 'MyText'
}

$Arraytest2 = @{
    TLC     = 'FWE'
    Crew3LC = 'KMU'
    MyText  = 'Hello'
}

foreach ($Value in $Arraytest) {
    $Value.Values
}

@JamesC. This will not create a clone, it sets a reference. Changes made to $arraytest will also be present in $arraytest2 — arco444
– arco444, Commented Jun 14, 2018 at 11:53
Edit fail, I'd deleted .Clone() somehow. Added as an answer instead. — henrycarteruk
– henrycarteruk, Commented Jun 14, 2018 at 12:42

henrycarteruk · Accepted Answer · 2018-06-14 12:40:55Z

Your objects are hashtables, not arrays:

$Arraytest | Get-Member

TypeName: System.Collections.Hashtable

So you can update using the built in hashtable keys:

$Arraytest = @{
    TLC      = 'TLC'
    Crew3LC  = 'Crew3LC'
    MyText   = 'MyText'
}

$Arraytest2 = @{ 
    TLC      = 'FWE'
    Crew3LC  = 'KMU'
    MyText   = 'Hello'
}

foreach($key in $($Arraytest.keys)){
    $ArrayTest[$key] = $ArrayTest2[$key] 
}

$ArrayTest

Name                           Value                                                                                                                                                                                 
----                           -----                                                                                                                                                                                 
Crew3LC                        KMU                                                                                                                                                                                   
TLC                            FWE                                                                                                                                                                                   
MyText                         Hello

henrycarteruk · Accepted Answer · 2018-06-14 12:39:59Z

0

You can use Clone() for a shallow copy:

$Arraytest = $Arraytest2.Clone()

A shallow copy will be fine for this case, but see Remarks for further info on this.

edited Jun 14, 2018 at 12:39

answered Jun 14, 2018 at 12:33

henrycarteruk

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