Delete an element from numpy array

Question

I am working with numpy array as follows:

  input_series =  ['BUY' 'SELL' 'BUY' 'SELL' 'BUY' 'SELL' 'SELL' 'SELL' 'BUY' 'SELL' nan nan
     nan nan nan nan nan nan nan]

I am searching for particular values in array and if element exist then delete

I have done this as follows:

delete_indices = list()
val = ['BUY','SELL','No','YES']
found_index = np.where(lowercase_series_nparray == val)                                                
delete_indices.append(found_index)

delete_indices getting as follows:

[(array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([0, 2, 4, 8], dtype=int64),), (array([1, 3, 5, 6, 7, 9], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),), (array([], dtype=int64),)]

Aftre that I am trying to delete with :

new_output_series = numpy.delete(input_series, delete_indices)

But getting error as setting an array element with a sequence.

Joe · Accepted Answer · 2018-06-07 06:33:55Z

5

If from an array like this:

input_series = np.array(['BUY', 'a', 'b', 'SELL', 'YES', 'SELL', 'No', 'c', 'd', 'SELL'])

you want to remove these elements:

['BUY','SELL','No','YES']

Just set these as an array:

val = np.array(['BUY','SELL','No','YES'])

and then:

new_output_series = np.setdiff1d(input_series,val)

Output:

 ['a' 'b' 'c' 'd']

answered Jun 7, 2018 at 6:33

Joe

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Comments

Nikhil Verma · Accepted Answer · 2018-06-07 06:22:53Z

2

Below statement gives you the indexes you need:

 found_index = np.in1d(input_series, val).nonzero()[0]

and then:

 new_array = numpy.delete(input_series, found_index)

answered Jun 7, 2018 at 6:22

Nikhil Verma

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