python check if a String is palindrome or not in an array [duplicate]

Question

For example I have this array:

array = ['b2', 'jy', 'n3', 'ih', 'fc']

And I am trying to access each index of the array to check if is palindrome or not.

for i in range(len(array[i])):

    if array[i] == array[len(pal)-i-1]:
        booleano = "true"

    else:
        booleano = "false"


if booleano != "true":
    return false

else: return true

What am I missing?

What exactly is wrong with the code you show? Read and follow How to create a Minimal, Complete, and Verifiable example. — Rory Daulton
– Rory Daulton, Commented May 17, 2018 at 13:57
This can also be useful to verify conditions in a list: secnetix.de/olli/Python/list_comprehensions.hawk — Jundiaius
– Jundiaius, Commented May 17, 2018 at 14:00

Mihai Alexandru-Ionut · Accepted Answer · 2018-05-17 14:06:41Z

3

You can check if string is palindrome using [::-1] slicing.

lst = ['bb', 'jhj', 'n3', 'ih', 'fc']
palindromes = [item == item[::-1] for item in lst]

Output

[True, True, False, False, False]

edited May 17, 2018 at 14:06

answered May 17, 2018 at 13:58

Mihai Alexandru-Ionut

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3 Comments

Chris_Rands Over a year ago

[item == item[::-1]] for item in lst] might be closer to what they asked for, also maybe debug their current code too

Afonso Pinto Over a year ago

Instead of that kind of output how can I have like: lst = ['bb true', 'jhj true', 'n3 false', 'ih false', 'fc false']

Mihai Alexandru-Ionut Over a year ago

@AfonsoPinto, something like this: palindromes = [item + ' '+ str(item == item[::-1]) for item in lst]

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