python3 numpy: too many indices for array

Question

I have a value, just like:

a = np.array({'a':1})

Then, I want to get the dict from a. But error happens when I use a[0]:

IndexError: too many indices for array

I have a look at the shape of a:

>>> a.shape
()

So, how to get the value from a?

galmeriol · Accepted Answer · 2018-05-15 11:03:22Z

2

You should create your array with list;

a = np.array([{'a':1}])

answered May 15, 2018 at 11:03

galmeriol

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1 Comment

In fact, I use numpy to save a dict. And after np.load, the value look like what I gave. The value is not created by me, but by np.load

BcK · Accepted Answer · 2018-05-15 11:04:58Z

1

You can access it like this,

import numpy

a = numpy.array({'a': 1, 'b': 2})
a.item()['a']
# 1

answered May 15, 2018 at 11:04

BcK

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a[()] is another way of accessing the element inside an 0d array.

NoorJafri · Accepted Answer · 2018-05-15 11:04:50Z

1

galmeriol is right. Go for as he has suggested.

>>> a.all()
{'a': 1}
>>>> a.all()['a']
1

answered May 15, 2018 at 11:04

NoorJafri

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