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So I am using this code to push new user IDs into an array but I get

Warning: array_push() expects at least 2 parameters, one given

$post_likes = array(
"Some key" => array(
             'date' => date("d/m/Y"), 
             'IP' => get_client_ip())
             ); 
$new_likes = array(
             'date' => date("d/m/Y"), 
             'IP' => get_client_ip());
array_push($post_likes[$current_user->ID] = $new_likes);

The code works. It pushes new key with array value into the previous array. But still I get that warning. What am I missing?

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  • 1
    Check this link. php.net/manual/en/function.array-push.php Commented May 7, 2018 at 5:22
  • I checked. Without using array push, it doesn't give me warning. But to use array push with key and value, they wrote this same thing. Also see the ans here - stackoverflow.com/questions/2121548/… used same method. But how come I get a warning? Could you please explain? Commented May 7, 2018 at 5:26
  • Check my answer below. I think you didn't check properly. Commented May 7, 2018 at 5:30
  • Have you tried just doing $post_likes[$current_user->ID] = $new_likes; without the array_push() at all? That will add a new key (the user ID) to the array with the $new_likes as value. Commented May 7, 2018 at 5:31
  • Yes I tried and it worked. Check my previous comment. @Magnus Eriksson I just wanted to know why this warning Commented May 7, 2018 at 5:33

2 Answers 2

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2

Instead of using array_push() you can directly do like this-

$post_likes[$current_user->ID] = $new_likes;

A sample hardcoded example:- https://eval.in/1000261

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-1

Set your new variable $new_likes as like this:

array_push($post_likes[$current_user->ID] = $new_likes,$new_likes);   //expects at least 2 parameters

More info : http://php.net/manual/en/function.array-push.php

Updated:

I am proffering and suggesting to use @Magnus Eriksson's answer though you have accepted my answer.

So, just use as like below:

$post_likes[$current_user->ID] = $new_likes;
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4 Comments

This might work, but it will throw a Notice, since array_push() wants the the first argument to be passed as reference (and there for wants an array, not the result of an expression).
@Magnus Eriksson Didn't show any notice. But I am still wondering, why!
@AsifurRahman - If it doesn't show a notice, it's because your error reporting hides notices. Demo: 3v4l.org/ot2Xu. This is the wrong way of doing it. You should accept Alivetodies's answer instead, since that's the correct way.
@Magnus Eriksson Oh didn't try it outside my environment. Thank you.

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