Encoding for embedding python in C++

Question

I'm trying to embed a python code in C++ and it compiles successfully but when I try to run my code, I get the following error.

File "./cppPython", line 1
SyntaxError: Non-ASCII character '\x88' in file ./cppPython on line 2, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details

These are my C++ and Python codes.

CPP code

#include <Python.h>
#include <iostream>

using namespace std;
int main(int argc, char *argv[])
{ 
  FILE *fp = fopen(argv[0],"r");
  Py_SetProgramName(argv[0]);  /* optional but recommended */
  Py_Initialize();

  PyRun_SimpleFileExFlags(fp,argv[0],0,NULL);

  Py_Finalize();
  return 0;
}

Python code

#!/usr/bin/env python
# -*- coding: utf-8 -*-
print "hello"

Yash Verma · Accepted Answer · 2018-05-02 09:13:26Z

1

argv[0] gives the C++ executable name. For eg. If you named the C++ executable as abc and executed as:

./abc pythonFileName.py

Then the argv array will have argv[0] as ./abc and argv[1] as pythonFileName.py.

So, please use the index 1.

answered May 2, 2018 at 9:13

Yash Verma

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Comments

Ignacio Vazquez-Abrams · Accepted Answer · 2018-05-02 08:58:27Z

1

You're running the executable as Python code, which it is not. Verify the arguments to fopen() and PyRun_SimpleFileExFlags().

answered May 2, 2018 at 8:58

Ignacio Vazquez-Abrams

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5 Comments

Abhishek Arya Over a year ago

Hello Ignacio. Thanks for your answer. Can you please explain your answer a bit? I couldn't understand what you said.

Ignacio Vazquez-Abrams Over a year ago

Do you understand what argv is?

Abhishek Arya Over a year ago

This is the way I'm running my cpp code ./cppPython cppPython.py. Basically, argv is the array containing the arguments that I pass to my c++ code.

Ignacio Vazquez-Abrams Over a year ago

"argv is the array containing the arguments that I pass to my c++ code" Incorrect. It is all words parsed from the command line, not just the arguments.

Abhishek Arya Over a year ago

Ohh, I got it. Thanks Ignacio. Now, I call fopen like fopen(argv[1],"r") and my code works as it should. Thanks again.

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