I have two lists:
f= ['A', 'A']
d = [(2096, 222, 2640), (1494, 479, 1285)]
I want a list!
LL = [('A', 2096, 222, 2640), ('A', 1494, 479, 1285)]
I am close with dic = zip(f,d)
but this give me this:
[('A', (2096, 222, 2640)), ('A', (1494, 479, 1285))]
How can i get LL?
Try:
LL = [ (x,) + y for x, y in zip(f, d) ]
This iterates through the convoluted arrays and adds the string outside the tuple to the tuple (by creating a new tuple, due to the fact tuples are immutable).
the zip command does that along with dict:
>>>dict(zip([1,2,3],[1,2,3]))
{1:1,2:2,3:3}
dictionary? ;) (and you name the variable dic btw which suggest to hold a dictionary, but this is me being nitpicking...)
You can also do this with map() instead of zip()
LL = map(lambda x,y:(x,)+y, f, d)
(x,) is equivalent to tuple(x)
LL = map(lambda x,y:tuple(x)+y, f, d)
[(x,) + y for x,y in zip(f, d)]
In fact you have a list of strings and a list of tuples. Tuples are immutable, so you will have to reconstruct each tuple.
For only 2 items you can try:
[tuple(f[0])+d[0], tuple(f[1])+d[1]]
For N number of items look for "list comprehension", for example here: http://docs.python.org/tutorial/datastructures.html or build them up using a loop if that is more understandable.
