Android sort array

Question

how can i sort this array by date or name?

String[][] datetable= new String[21][2];

datetable[0][0] = "2011.01.01";
datetable[0][1] = "Name1";
datetable[1][0] = "2011.01.03";
datetable[1][1] = "Name2";
.
.
.
datetable[20][0] = "2011.02.16";
datetable[20][1] = "Name3";

possible duplicate of Sort a two dimensional array based on one column — andri
– andri, Commented Feb 12, 2011 at 21:31

Edawg · Accepted Answer · 2011-02-12 21:35:23Z

8

I would do what the poster linked to, only I wouldn't use final so much.

Arrays.sort(datetable, new Comparator<String[]>() {
    @Override
    public int compare(String[] entry1, String[] entry2) {
        // Sort by date
        return entry1[0].compareTo(entry2[0]);
    }
});

answered Feb 12, 2011 at 21:35

Edawg

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Community · Accepted Answer · 2017-05-23 11:47:45Z

1

This may help: Sort a two dimensional array based on one column

edited May 23, 2017 at 11:47

CommunityBot

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answered Feb 12, 2011 at 21:29

evergreen

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4 Comments

erdomester Over a year ago

Looks good. I would like to paste some code here how to do that? –

erdomester Over a year ago

Thank you! Thats is the simple solution what i was looking for!

erdomester Over a year ago

In certain languages there are special letters. In Hungary we have also e.g. Á, which follows letter A. In this sorting procedure words starting with these letters are at the end of the of the array. Is there a way to handle this?

evergreen Over a year ago

It's a matter of how you override the "compare" function. In that code example, the "compare" function simply uses the default String.compareTo() to sort strings. The reason you found those words are put to the end is probably because their unicode is bigger than the unicode of any English letters. If you want to put Á right after A, you will need to implement a more sophisticated "compare" function.

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