Variables in Array (PHP)?

Question

I have a simple iPhone application I am making that will upload pictures to Facebook. To do this, I have to put multiple files on the server. From that, it will go to Facebook. I have my PHP code below that will do that server-side.

The problem is, when I put a variable in the array, it won't work. I have tried all the different options and it's not working out for me.

Any help is appreciated! Thanks.

$args = array(
'message' => 'Photo from the ******** iPhone Application.',
'$short_url' => '$short_url'
);

$url = 'https://graph.facebook.com/'.$album_id.'/photos?access_token='.$get_facebook_token;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $args);
$data = curl_exec($ch);
//returns the photo id
print_r(json_decode($data,true));

Okay, all the quotations look fine here, what do you get as a result, and what were you expecting? — Jake Lee
– Jake Lee, Commented Feb 12, 2011 at 2:20
What is this? '$short_url' => '@$short_url' | Try 'short_url' => $short_url in its place. Single quotes '', do not interpolate. — Orbling
– Orbling, Commented Feb 12, 2011 at 2:21
Thanks for all the comments! Here's what I had to do: - I removed the '' and facebook didn't reconize it. - I figured it had to do something with the mysql code so I did it a little different and it worked. Now they go to a database, and I run a cron job with it every minute to do it. I think it's a better method because if it fails, It can run again. — iosfreak
– iosfreak, Commented Feb 12, 2011 at 21:59

mario · Accepted Answer · 2011-02-12 02:22:39Z

2

You are using single quotes were you probably should be using a variable directly or double quotes so the variable gets interpolated:

$args = array(
    ...,
   "short_url" => "@$short_url",
);

Or something like that. Depends on the supposed form field names. And "@$var" probaby leads to a file upload with curl.

answered Feb 12, 2011 at 2:22

mario

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Comments

score 1 · Accepted Answer · 2011-02-12 02:34:55Z

1

Remove the ''s around the variable so it won't be treated as a string.

$args = array(
 'message' => 'Photo from the ******** iPhone Application.',
 'short_url' => $short_url
);

edited Feb 12, 2011 at 2:34

answered Feb 12, 2011 at 2:20

user142162

1 Comment

zerkms Over a year ago

do you think it is what he needs?

Foo Bah · Accepted Answer · 2011-02-12 02:28:49Z

0

You probably need

"short_url" => $short_url

answered Feb 12, 2011 at 2:28

Foo Bah

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