Problem in converting Hexadecimal value to bigInteger

Question

I have a string uniqueCode of length 16.

String uniqueCode = accountno + extracode;

accountno is of length 6 and extracode is populated in following way:

String extraCode = branch + loanCode + openingDateStr ;
BigInteger hexaCode = new BigInteger(extraCode); 
extraCode = hexaCode.toString(16); // hexa bit

Now i want to get back branch,loancode and openingdatestr from this uniquecode. how to do this?

Why does this need to be a BigInteger? You only normally convert to an integer if you want to perform some form of math operation on it. If it's simply an identifier you can leave it as a String. — trojanfoe
– trojanfoe, Commented Feb 11, 2011 at 7:59

Vijay Mathew · Accepted Answer · 2011-02-11 08:04:10Z

1

To get back the original string from extraCode in hex:

BigInteger decCode = new BigInteger(extraCode, 16);
extraCode = decCode.toString(10);

Now you can extract the components from extraCode by their length. For instance, if branch has 6 digits and loanCode has 4 digits, you can do:

String branch = extraCode.substring(0, 6);
String loanCode = extraCode.substring(6, 10);

edited Feb 11, 2011 at 8:04

answered Feb 11, 2011 at 7:58

Vijay Mathew

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