I have an array that matches the parameters of a function:
TmpfieldNames = []
TmpfieldNames.append(Trademark.name)
TmpfieldNames.append(Trademark.id)
return func(Trademark.name, Trademark.id)
func(Trademark.name.Trademark.id) works, but func(TmpfieldNames) doesn't. How can I call the function without explicitly indexing into the array like func(TmpfieldNames[0], TmpfieldNames[1])?
With * you can unpack arguments from a list or tuple and ** unpacks arguments from a dict.
>>> range(3, 6) # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args) # call with arguments unpacked from a list
[3, 4, 5]
Example from the documentation.
I think what you are looking for is this:
def f(a, b):
print a, b
arr = [1, 2]
f(*arr)
What you are looking for is:
func(*TmpfieldNames)
But this isn't the typical use case for such a feature; I'm assuming you've created it for demonstration.
len(fieldNames)copies of (references to)Tademark.id, then return the result of some function called with a singleTrademark.nameandTrademark.id. (Edit: Okay, that makes more sense)