How to remove all the element which equal to certain value in an array swift 4?

Question

I have a NSObject class look like this:

class MyItem : NSObject {

    var id: Int
    var name: String

    //other init code here
 }

So the array I define like this

var myItem = [MyItem]()

Here is the sample of my array:

{
"id" : 2
"name" : "Ali"

"id" : 3
"name" : "janice"

"id" : 2
"name" : "Ali"

"id" : 5
"name" : "tupac"

"id" : 2
"name" : "Ali"

"id" : 8
"name" : "William"

"id" : 2
"name" : "Ali"  
}

What I want to do is,write a function to remove all the element with the id which is equal to 2,so the array just left the element with id equal to [3,5,8].

I tried this code,but it just remove 1 element only but I want to remove all four element with id = 2

func removeId(id : Int){
  //find the index 1st
   guard let foundIndex = myItem.index(where: { $0.id == id }) else { return }
   myItem.remove(at: foundIndex)
}

Somebody please help,Thank you

Gereon · Accepted Answer · 2018-04-01 11:48:04Z

1

Use filter:

func removeId(id: Int) {
   myItem = myItem.filter { $0.id != id }
}

answered Apr 1, 2018 at 11:48

Gereon

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Comments

Zahurafzal Mirza · Accepted Answer · 2018-04-02 06:55:16Z

1

You can use filter() predicate to filter your array as show below

var myArray = ["Hello","Coding","World"]

myArray = myArray.filter{$0 != "Hello"}

print(myArray)   // "[Coding, World]"

answered Apr 2, 2018 at 6:55

Zahurafzal Mirza

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