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I want to find a 2d array in a 3d array. for finding a 1d array in a 2d array I can use np.where(np.all(a==b, axis=1))[0][0].

>>> import numpy as np
>>>
>>> a = np.array([[[1, 0, 0],
                   [0, 0, 0],
                   [0, 0, 0]],

                  [[0, 0, 0],
                   [0, 0, 0],
                   [0, 0, 0]]])
>>>
>>> b = np.array([[1, 0, 0],
                  [0, 0, 0],
                  [0, 0, 0]])
>>>
>>> a.find(b)
0
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  • It's almost the same. You just need to use the proper axis and maybe use another all method. Commented Apr 1, 2018 at 8:14

1 Answer 1

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The axis keyword accepts tuples, so you can simply do:

np.where(np.all(a==b, axis=(1, 2)))[0][0]
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