Looping in XSLT

Question

I have the following XML

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet href="sample.xsl" type="text/xsl"?>
<rss version="2.0"
 xmlns:atom="http://www.w3.org/2005/Atom"
 xmlns:cf="http://www.microsoft.com/schemas/rss/core/2005"
 xmlns:dc="http://purl.org/dc/elements/1.1/">
    <channel
     xmlns:cfi="http://www.microsoft.com/schemas/rss/core/2005/internal">
        <title cf:type="text">The Hindu - Front Page</title>
        <link>http://www.hindu.com/</link>
        <description cf:type="text">The Internet edition of The Hindu,
            India's national newspaper</description>
        <image>
            <url>http://www.hindu.com/hindu/hindux.gif</url>
            <title>hindu.com</title>
            <link>http://www.hindu.com/</link>
        </image>
        <item>
            <title cf:type="text"
             xmlns:cf="http://www.microsoft.com/schemas/rss/core/2005"
             >ISRO spectrum deal under review: Centre</title>
        </item>
        <item>
            <title cf:type="text"
             xmlns:cf="http://www.microsoft.com/schemas/rss/core/2005"
             >Response from Devas</title>
        </item>
    </channel>
</rss>

The rss/channel/item can be of any count(in the current case it's count is 2). I need to display the Titles as a Marquee one after the other as follows

ISRO spectrum deal under review: Centre, Response from Devas,....,....

How can I accomplish this in XSLT? kindly advice

Thanks

Flack · Accepted Answer · 2011-02-09 08:04:13Z

2

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:cfi="http://www.microsoft.com/schemas/rss/core/2005/internal"
    xmlns:cf="http://www.microsoft.com/schemas/rss/core/2005"
    xmlns:dc="http://purl.org/dc/elements/1.1/"
    exclude-result-prefixes="cfi cf dc">
    <xsl:output method="html" indent="yes"/>

    <xsl:template match="/*">
        <div id="marquee">
            <xsl:apply-templates select="channel/item/title"/>
        </div>
    </xsl:template>

    <xsl:template match="title">
        <xsl:value-of select="."/>
        <xsl:if test="not(position() = last())">, </xsl:if>
    </xsl:template>

</xsl:stylesheet>

Result against your sample:

<div id="marquee">ISRO spectrum deal under review: Centre, Response from Devas</div>

answered Feb 9, 2011 at 8:04

Flack

5,8572 gold badges26 silver badges27 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

padLing Over a year ago

Cool....this works thanks a ton for your help. BTW, can you suggest any good books for XSL.

Flack Over a year ago

@padLing, then you should accept the answer (just click on the checkmark to the top left of my answer).

Flack Over a year ago

@padLing, for books check this question: stackoverflow.com/questions/339930/…

user357812 · Accepted Answer · 2011-02-09 17:16:33Z

1

In addition to @Flack correct answer, in XSLT 2.0 xsl:value-of instruction preserves sequence. So, this stylesheet:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
        <div id="marquee">
            <xsl:value-of select="rss/channel/item/title"
                          separator=", "/>
        </div>
    </xsl:template>
</xsl:stylesheet>

Also outputs:

<div id="marquee"
 >ISRO spectrum deal under review: Centre, Response from Devas</div>

answered Feb 9, 2011 at 17:16

user357812

1 Comment

Nick Jones Over a year ago

+1 - I didn't know about separator despite having implemented it!

Collectives™ on Stack Overflow

Looping in XSLT

2 Answers 2

3 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related