a=[('https://www.google.co.in/search?q=kite+zerodha&oq=kite%2Cz&aqs=chrome.1.69i57j0l5.4766j0j7&sourceid=chrome&ie=UTF-8', 1), ('https://kite.zerodha.com/', 1), ('https://kite.trade/connect/login?api_key=xyz', 1)]
how to get value of api_key which is xyz from above mentioned a.
please help me to write code in python.Thank you
Just looping over all elements and parsing url to get the api_key, have a look into below code:
from urlparse import urlparse, parse_qs
a=[('https://www.google.co.in/search?q=kite+zerodha&oq=kite%2Cz&aqs=chrome.1.69i57j0l5.4766j0j7&sourceid=chrome&ie=UTF-8', 1), ('https://kite.zerodha.com/', 1), ('https://kite.trade/connect/login?api_key=xyz', 1)]
for value in a:
if len(value) > 1:
url = value[0]
if 'api_key' in parse_qs(urlparse(url).query).keys():
print parse_qs(urlparse(url).query)['api_key'][0]
output:
xyz
This will work too. Hope this helps.
- Find all items that has the keyword 'api_key' (in url[0]),
- Split it into columns, delimited by '=' (split by '=')
- The last entry ([-1]) will be the answer (xyz).
a=[('https://www.google.co.in/search?q=kite+zerodha&oq=kite%2Cz&aqs=chrome.1.69i57j0l5.4766j0j7&sourceid=chrome&ie=UTF-8', 1), ('https://kite.zerodha.com/', 1), ('https://kite.trade/connect/login?api_key=xyz', 1)]
for ky in [url for url in a if 'api_key' in url[0]]:
print(ky[0].split('=')[-1])
Sample result: xyz
