If you write like
n = str(input())
n = n.split()
print(n)
That will work. But if you try to do it with integers, you will get
`Value Error`.
How to do it with int type?
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Please format as codeMad Physicist– Mad Physicist2018-03-02 07:53:48 +00:00Commented Mar 2, 2018 at 7:53
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Show the error. I'm unable to reproduce your problem.Mad Physicist– Mad Physicist2018-03-02 07:54:27 +00:00Commented Mar 2, 2018 at 7:54
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Pleas show your simple code.William Feirie– William Feirie2018-03-02 08:18:15 +00:00Commented Mar 2, 2018 at 8:18
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to split a string with no delimiter ( like space or comma), have a look at : this question ...but, an error cannot be the result of the above code unless the result of input() is not simply an integer.manandearth– manandearth2018-03-02 08:25:00 +00:00Commented Mar 2, 2018 at 8:25
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3 Answers
Do you want to separate several numbers? 1 2 3 -> [1, 2, 3]
n = str(input())
n = n.split()
numbers = [int(i) for i in n]
print(numbers)
Or split a number in numeral? 123 -> [1, 2, 3]
n = str(input())
numbers = [int(i) for i in n]
print(numbers)
Use Nikhil answer, if you want to split a number with delimiters 1%3 -> [1, 3]
Comments
You can split integer value with following ways..
list comprehension
n = str(input()) result = [x for x in n] print(result)
using list object
n = str(input()) result = [x for x in n] print(result)using map object
n = str(input()) result = list(map(int,n)) print(result)
Comments
You can do that like this,
n = 567
a = str(n).split(YOUR DELIMITER)
Like if YOUR DELIMITER = 6,
Then if i print(a) then i get,
['5', '7']
