The following question has helped me solving the problem of executing multiple SQL Scripts located in file. Run all SQL files in a directory However, I did not get how to redirect the output into a separate log file. Someone suggested the following script but since I don't understand it, it did not work and I can't find out the error.
for %f in (*.sql) do sqlcmd /S <servername> /d <dbname> /E /i "%f" >> sql.log 2>&1)
If you need the output into one common file then you should use the @Abhishek 's answer.
If you need the output into a separate log file for an each input sql file
then you can use -o parameter of sqlcmd command. Your bat file could look like this:
for %%G in (*.sql) do sqlcmd /S <servername> /d <dbname> -E -i"%%G" -o C:\logs\%%G.log
pause
In this case for
1.sql
2.sql
you will get:
1.sql.log
2.sql.log
for %%G in (*.sql) do (sqlcmd /S <servername> /d <dbname> -E -i "%%G" > C:\logs\%%~nG.log) In this case, for file1.sql and file2.sql you will get file1.log and file2.logYou are seeking Command Redirection.
As per your example -
for %f in (*.sql) do sqlcmd /S <servername> /d <dbname> /E /i "%f" >> sql.log 2>&1
once the execution of the sql script is done the output will be redirected to and appends the command output to the end of file (here sql.log) without deleting the information that is already in the file (>>) and redirects STDERR (2) into STDOUT handle(1) - 2>&1
