Change foreach $key variable inside the foreach loop

Question

Looking for a way to change $$key to something like $$key_errorso the variable will look something like: $name_error outside the foreach loop.

Here is what I have so far:

  foreach ($_POST as $key => $value) {
    $$key = strip_tags(mysqli_real_escape_string($mysqli, $value));
     if (empty($value)) {
       // change variable below to something like $$key_error ($$name_error)
       $$key = 'is-invalid';

     } else {
       $$key = "value='$value'";
     }
  }

When an input is empty the user will return to the registration form, the input that is empty will have red bootstrap borders. When a field is not empty, the value will still be there so they do not have to do it all over.

<input type="text" name="name" class="form-control form-control-lg <?=$name?>" style="text-align:center;" placeholder="Voor- en achternaam" <?=$name?>>

I hope it all makes sense :)

Why? Anytime you use variable variables you should probably be using an array, which you already are using. Or build another $errors array. — AbraCadaver
– AbraCadaver, Commented Feb 27, 2018 at 19:38

Don't Panic · Accepted Answer · 2018-02-27 20:01:50Z

1

Use arrays.

$errors = [];
$values = [];

foreach ($_POST as $key => $value) {
    // validation check for $value
    if (/*validation check fails*/) {
       $errors[$key] = 'error message specific to this field';
    } else {
        $values[$key] = htmlspecialchars($value);
    }
}

Then in your form, check for the array key matching your control name.

<input type="text" name="example"
    class="<?= isset($errors['example']) ? 'is-invalid' : '' ?> other classes"
    value="<?= $values['example'] ?? '' ?>">

You can also output the specific error message if you want to.

<div class="error"><?= $errors['example'] ?? '' ?></div>

answered Feb 27, 2018 at 20:01

Don't Panic

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