Python - call function within itself (same parameters)

Question

I am calling the same function within itself.

base_url="www.myurl.com"
urls_1="www.myurl.com/1"
urls_2="www.myurl.com/2"
rep_1="/report1"
rep_2="/report2"

    def get_response(url, report):
      response=requests.get(url,report, headers=header)
      data=response.json()

      if (len(data))==100:
          header.update({"range":rep + str(range_from + 100) + "-" + 
          str(range_to + 100)})
          **data2=get_response(?,?)**

     else:
         return data

When I call the function inside, I want to use the same parameters that I used to call the outer function.(Only writing the function once)

This outer function gets called hundreds of times with all different parameters; sometimes it gets called within a for loop.

Thanks in advance.

What's the problem? You are probably finding RuntimeError: maximum recursion depth exceeded? The reason why should be obvious... — innisfree
– innisfree, Commented Feb 6, 2018 at 0:37

samrap · Accepted Answer · 2018-02-06 00:37:40Z

3

What you're attempting is known as recursion in computer science.

def my_function(x,y,z): 
    something = my_function(x, y, z)

However, this is going to throw you into an infinite loop. For recursion to work, you have to have a base case -- a way of stopping -- and then simplify the problem at each step. See on-line tutorials and examples of recursion.

edited Feb 6, 2018 at 0:37

samrap

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answered Feb 6, 2018 at 0:34

Prune

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2 Comments

ShadowRanger Over a year ago

@Paul: Edit the code into your question; comments can't format code, which is especially important for Python.

Prune Over a year ago

Please follow the posting guidelines. Among other things, any code needs to be in readable format: edit it into your original question, not into a comment.

Paul · Accepted Answer · 2018-02-14 03:26:07Z

0

data2=get_response(url, report)

answered Feb 14, 2018 at 3:26

Paul

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