Replace pattern with pattern in vb.net string

Question

I want to replace "0A ","0B ",...,"1A ","1B ",... patterns with "0A|","0B|",...,"1A|","1B|",... from string vb.net

I can write individual replace lines like

string = string.Replace("0A ", "0A|")
string = string.Replace("0B ", "0B|")
.
.
.
string = string.Replace("0Z ", "0Z|")

But, I would have to write too many lines(26*10*2- Two because such scenario occurs twice) and it just doesn't seem to be a good solution. Can someone give me a good regex solution for this?

Try (?<="[a-z\d]+) (?=") replace with | using IgnoreCase — ctwheels
– ctwheels, Commented Jan 30, 2018 at 16:05
Show the data structure of template string which you want replace it's letters by your new template please. — Milad Rashidi
– Milad Rashidi, Commented Jan 30, 2018 at 16:07

Tim Biegeleisen · Accepted Answer · 2018-01-30 16:04:59Z

1

Use Regex.Replace:

result = Regex.Replace(string, "(\d+[A-Z]+) ", "$1|")

I used the pattern \d+[A-Z]+ to represent the text under the assumption that your series of data might see more than one digit/letter. This seems to be working in the demo below.

Demo

answered Jan 30, 2018 at 16:04

Tim Biegeleisen

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1 Comment

NRB Over a year ago

Worked, Thanks a lot

Srdjan M. · Accepted Answer · 2018-01-30 16:28:50Z

0

Regex: \s Substitution: |

Details:

\s Matches any whitespace character

Regex demo

VB.NET code:

Regex.Replace("0A ", "\s", "|") Output: 0A|

edited Jan 30, 2018 at 16:28

answered Jan 30, 2018 at 16:23

Srdjan M.

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