Filter two values in array of objects

Question

I have an array of objects and I want to filter them by two conditions, either if object is in an certain group or if it has an certain name but I can not figure out why it is not working.

This is my code:

let outputfiler = array.filter({$0.group.contains (where: {$0 == "groupBig" }) } || $1.name.contains(where: {$1 == "Eis"})  )

This is the error I get:

Anonymous closure argument not contained in a closure

Edit: Group is an array of trings, name just a string.

I also tried this:

outputfiler = array.filter{$0.group.contains (where: {$0 == "groupBig" }) || $0.name(where: {$0 == "Eis"}) }

But then I get this error:

Extraneous argument label 'where:' in call

Filter takes a single closure, you can have multiple boolean expressions within the closure. So start by ensuring your array.filter is followed by { rather than (. — cptwonton
– cptwonton, Commented Jan 25, 2018 at 18:00
if name is a String property, $0.name(where:) doesn't really make sense. Are you trying to test if contains the substring "Eis" or is equal to "Eis"? In the latter case, use array.filter{ $0.group.contains("groupBig") || $0.name == "Eis" }. In the former, contains(where:) only deals with Character so you need a different API — Peter E
– Peter E, Commented Jan 25, 2018 at 22:12

rmaddy · Accepted Answer · 2018-01-25 18:13:54Z

5

You need your filter as follows (shown on multiple lines for clarity):

let outputfiler = array.filter({
    $0.group.contains(where: { $0 == "groupBig" }) || 
    $0.name.contains("Eis")
})

You had the filter's closing } before the ||. And assuming name is a String, contains just takes the string to search, not a closure.

edited Jan 25, 2018 at 18:13

answered Jan 25, 2018 at 18:05

rmaddy

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3 Comments

PaFi Over a year ago

i tried this but xcode tells me "Extraneous argument label 'where:' in call" i should delete the secont "where".

rmaddy Over a year ago

Is name a String or an array of String? See the update that assumes it is a String and not an array.

PaFi Over a year ago

yes thanks sorry my fault, yes group was an array of strings and name just an string. It works now, thanks again

Phyber · Accepted Answer · 2018-01-25 18:13:52Z

1

This syntax should work.

let outputfiler = array.filter{$0.group.contains("groupBig") || $0.name.contains("Eis")}

answered Jan 25, 2018 at 18:13

Phyber

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Comments

Danielvgftv · Accepted Answer · 2019-09-15 00:48:23Z

This is my solution in Swift 5 (Example 👇🏽👇🏽👇🏽):

My struct (I use this struct for extract data from Firebase):

struct User { 

    let uid:String
    let phoneNumber:String
    let username:String
    let email:String

    init(uid:String, dictionary: [String: Any]) {
        self.uid = uid
        self.username = dictionary["username"] as? String ?? String()
        self.phoneNumber = dictionary["phoneNumber"] as? String ?? String()
        self.email = dictionary["email"] as? String ?? String()

    }

}

Filter:

let arrayFiltered =  self.arrayUsers.filter { (user) -> Bool in
    return user.username.lowercased().contains("Dani".lowercased()) ||
           user.email.lowercased().contains("[email protected]".lowercased()) ||
           user.phoneNumber.lowercased().contains("+34111223344".lowercased())

}

Have a good day ♥️.

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