Getting array data from PHP to jQuery for outputting

Question

Here is the partial code from the remove PHP file:

if($action == 'trackings_get') {
    $result = $trackings->get(getCourierSlugByID($GLOBALS['tracking_id']), $GLOBALS['tracking_id']);
    $result_history = $result['data']['tracking']['checkpoints'];

    echo json_encode($result_history);

    // debugging
    //pretty_print($result_history);
}

Here is the JS from the remote site i am trying to call the data for:

$.ajax({
  url: '/login/tracking.php',
  type: 'POST', 
  dataType: "json",
  data: {
    action: action,
    tracking_id: tracking_id
  }, 
  success: function(json){ 
    //debug
    alert(JSON.stringify(json));
  }
});

convert alert(JSON.stringify(json)); to console.log(json); and see what is coming in console. Now you can use that json (if output is coming fine.) . You used dataType: "json", so no need of JSON.stringify() — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Dec 7, 2017 at 5:56
I tried that but nothing was returned, and look in network i see the POST but no result, if i change to GET i see the returned array though but not sure right way to get this data and handle it... — James
– James, Commented Dec 7, 2017 at 6:00
change POST to GET and then try to use the data according to your wish — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Dec 7, 2017 at 6:00

ali 20 developer · Accepted Answer · 2017-12-07 17:14:59Z

1

try this

function test(){
$.ajax({
  url: 'url',
  type: 'POST', 
  dataType: "json",
  data: {
    action: action,
    tracking_id: tracking_id
  }, 
  success: function(json){ 
  }
});


}

answered Dec 7, 2017 at 17:14

ali 20 developer

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Comments

ali zarei · Accepted Answer · 2017-12-13 06:31:20Z

1

i try this code in inspect element in this page https://tracking.ambientlounge.com/

function test(){
$.ajax({
  url: 'your url',
  type: 'POST', 
  dataType: "json",
  data: {
    action: "action",
    tracking_id: "tracking_id"
  }, 
  success: function(json){ 
    //debug
    console.log(json);
  }
});


}

result is array . dont need JSON.stringify .

edited Dec 13, 2017 at 6:31

answered Dec 7, 2017 at 6:09

ali zarei

1,25111 silver badges18 bronze badges

4 Comments

Death-is-the-real-truth Over a year ago

ali zarei you used hardcoded value in url and hens POST method and data sending become useless. That's not the right way to do so

ali zarei Over a year ago

it is a sample only !!

Death-is-the-real-truth Over a year ago

then it's wrong way to giving sample. This sample will serve future visitors too. So it will misguide them as well.

James Over a year ago

Yes I agree, can you please modify this Answer as dont want URLs or screenshots to this system. I have adjusted the questiont o remove the POST URL to remove this but please adjust your reply.

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