While using Turbo c++ initializing array of char variable getting error code as follows
int gd=DETECT,gm,i,d=0,x,y;
char s[12]={"3","4","5","6","7","8","9","10","11","12","1","2","\0"};
initgraph(&gd,&gm,"..\\BGI");
but while used to initialize s[12][3], the initializer list works fine!
There is a difference between "3" and '3'.
"3" is a string literal'3' is a character constant (to nitpick: integer character constant)here, to initialize an array of char type, you seem to need (brace-enclosed) list of character constants, not strings.
but while using s[12][3] works fine
Well, there you're initializing arrays.
Moral of the story: When in doubt, check the data types!!
You need to change:
char s[12]={"3","4","5","6","7","8","9","10","11","12","1","2","\0"};
to
char s[13]={'3','4','5','6','7','8','9','10','11','12','1','2','\0'};
As char array elements should be char literals not string literals
You are trying to store chars, not strings, so why do you use double quotes?
"a" is a string, 'a' is a character.
What you actually want to store is strings, and for that you need a 2D array, like this:
s[12][3] = {"3","4","5","6","7","8","9","10","11","12","1","2"};
You cannot express 10 as a single character, I mean '10' does not exist. Single characters are from 0 to 9 when it comes to digits. For that reason, you need a string for 10, like this "10".
Now, you need the second dimension of your array to be 3, because the string "10" (for example) is a null-terminated string, thus 2 characters for its actual contents, plus one for the null-terminator, gives as 3.
PS: Turbo-C++ is an ancient compiler. Upgrade to GCC or anything else, really.
{"3","4","5","6","7","8","9","10","11","12","1","2","\0"};is not an array of characters. What else did you expect to happen? Also FYI, Microsoft DOS has no future, get a modern compiler.'3'& c. areinttypes in C, andchartypes in C++.