How to change the keys in one object with javascript?

Question

I have:

    var myAbc = { 0: true, 1: false, 2: true };

and i want to change de keys like:

var myAbc = { key1: true, key2: false, key3: true };

i have already tried this:

 for (var key in array) {
            key = value;
        }

but did not change the key of the array out side of the for, any help?

Possible duplicate of Changing the key name in an array of objects? — Sash Sinha
– Sash Sinha, Commented Nov 10, 2017 at 0:59

Derek 朕會功夫 · Accepted Answer · 2017-11-10 00:57:51Z

3

Something like this perhaps?

for(let key in myAbc){
    myAbc["key" + key] = myAbc[key];
    delete myAbc[key];
}

var myAbc = { 0: true, 1: false, 2: true };
console.log("Before", myAbc);

for(let key in myAbc){
    myAbc["key" + key] = myAbc[key];
    delete myAbc[key];
}
console.log("After", myAbc);

answered Nov 10, 2017 at 0:57

Derek 朕會功夫

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2 Comments

Mark Over a year ago

You're right -- this is better if you actually want to change the object rather than create a new one.

Marie Over a year ago

This is shorter and easier to follow, +1

CRice · Accepted Answer · 2017-11-10 01:01:36Z

1

If you can use es6, you can do this in one line:

var myAbc = { 0: true, 1: false, 2: true };

var renamed = Object.keys(myAbc).reduce((p, c) => { p[`key${Number(c)+1}`] = myAbc[c]; return p; }, {})

console.log(renamed)

answered Nov 10, 2017 at 1:01

CRice

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1 Comment

CRice Over a year ago

As noted by @Derek朕會功夫, this creates a new object with your desired keys (which is not the same as renaming existing keys). It can be reassigned back onto myAbc, but any existing references to myAbc will not be updated. If you want to mutate the object, Derek's answer will do that. That said, imo, you should avoid mutation anyway.

Wasim · Accepted Answer · 2017-11-10 01:23:45Z

1

Try this function:

function changeObjectKeys(sourceObject, prepondText){
    var updatedObj = {};
    for(var key in sourceObject){
        updatedObj[prepondText + key] = sourceObject[key];
    }
    return updatedObj;
}

Check here

answered Nov 10, 2017 at 1:23

Wasim

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