Retrieve Object from complex Array

Question

I have this array :

var hemicycle = {

    Group1 : [{
      GroupName : "Les bests",
        Member1 : [{
            Name : "Loris Plasson",
            Seat : 4,
            Vignette : "PhotoURL"
        }],
        Member2 : [{
          Name : "Anne-Sophie",
          Seat : 3,
          Vignette : "PhotoURL"
      }]

    }]

I want to push the object Member1 or Member2 on another object depending of the Seat value.

To do that I think I need to "search" for the Seat value with a for loop and retrieve the object, but all the examples I found on StackOverflow were with simple arrays like this :

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

With those simple arrays they are able to use something like a for loop with array[i].

But in my case I really don't know what to do...

UPDATE : What I want : The Member object which include the corresponding Seat value searched. Then I push the Member object to another object.

Thanks for any help.

but each member is an array as well, for example ` Member1 : [{ Name : "Loris Plasson", Seat : 4, Vignette : "PhotoURL" }],`. Why should it be an array? — Ori Drori
– Ori Drori, Commented Oct 26, 2017 at 14:24
This is how your data should look: hemicycle = [ { GroupName : "Les bests", members: [{ Name : "Loris Plasson", Seat : 4, Vignette : "PhotoURL" }, { Name : "Anne-Sophie", Seat : 3, Vignette : "PhotoURL" }] } ] — Ori Drori
– Ori Drori, Commented Oct 26, 2017 at 14:42
It's an array of groups. Each group is an object, that has the members property, which is an array of member objects. — Ori Drori
– Ori Drori, Commented Oct 26, 2017 at 14:44
You're welcome :) I've added an answer that includes how to find the member. Your solution won't work if the member is in the 2nd group. — Ori Drori
– Ori Drori, Commented Oct 26, 2017 at 18:14

Ori Drori · Accepted Answer · 2017-10-26 18:13:17Z

The data structure that you use doesn't reflect what you are trying to convey, and in addition is very heard to traverse.

I suggest creating an array of groups. Each group is an object, that has the members property, which is an array of member objects:

[{
  "GroupName": "Les bests",
  "members": [{
      "Name": "Loris Plasson",
      "Seat": 4,
      "Vignette": "PhotoURL"
    },
    {
      "Name": "Anne-Sophie",
      "Seat": 3,
      "Vignette": "PhotoURL"
    }
  ]
}]

Using this structure, you find a member using 2 for loops - one to iterate the groups, and the other to iterate the members of each group. Once a member is found, the function returns the member's object immediately. If not undefined is returned:

var groups = [{"GroupName":"Les bests","members":[{"Name":"Loris Plasson","Seat":4,"Vignette":"PhotoURL"},{"Name":"Anne-Sophie","Seat":3,"Vignette":"PhotoURL"}]}];

var seatNum = 4;

function findMember(seatNum) {
  var members;
  for(var i = 0; i < groups.length; i++) {
    members = groups[i].members;
    for(var j = 0; j < members.length; j++) {
      if(members[j].Seat = seatNum) {
        return members[j];
      }
    }
  }
}

var member = findMember(seatNum);

console.log(member);

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