Python XML parsing with XML

Question

I stuck with additional tag in XML. I have following XML

<result>
 <job>
    <tenq>15:37:53</tenq>
    <tdeq>15:37:53</tdeq>
    <tlast>15:37:53</tlast>
    <status>FIN</status>
    <id>168</id>
  </job>
  <log>
    <logs count="20" progress="100">
      <entry logid="6476178463223293277">
        <domain>1</domain>
        <receive_time>2017/10/13 15:37:50</receive_time>
        <serial>001801035328</serial>
        <seqno>6291444553</seqno>
        <----SKIP---->
        <pkts_received>0</pkts_received>
        <session_end_reason>policy-deny</session_end_reason>
        <action_source>from-policy</action_source>
      </entry>
      <----SKIP---->
    </logs>
  </log>
  <meta>
    <devices>
      <entry name="localhost.localdomain">
        <hostname>localhost.localdomain</hostname>
        <vsys>
          <entry name="vsys1">
            <display-name>vsys1</display-name>
          </entry>
        </vsys>
      </entry>
    </devices>
  </meta>
</result>

To get info about status I do following

    xml_parsed = ET.fromstring(resp.text)
    response_parsed = xml_parsed[0]
    resp_elems = response_parsed.findall('job')

Then I should receive number of log records and read all log entry. To get logs I am again start with:

    response_parsed = xml_parsed[0]
    resp_elems = response_parsed.findall('log')
    job_status = resp_elems[0].find('entry')

How to get logs count ? Are more elegant way exists to parse info ?

adder · Accepted Answer · 2017-10-13 11:02:57Z

1

You can use xml.etree.ElementTree.Element.items() to get the element attributes as a sequence of (name, value) pairs. Do keep in mind that the attributes are returned in an arbitrary order, so it is likely that you'd have to do some equality or membership checking to extract the info you need:

import xml.etree.ElementTree as ET

xml_str = """<result> ... </result>"""

tree = ET.fromstring(xml_str)

for x in tree.find('log'):
    print(x.items()) # [('count', '20'), ('progress', '100')]
    print(''.join(y[1] for y in x.items() if 'count' in y[0])) # 20

answered Oct 13, 2017 at 11:02

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