PHP To Check If Variable Is Set

Question

I am wanting to use one page that is linked to from two different pages. Below are my scenarios:

1) The user clicks a hyperlink to be directed to the page with a salesID in the URL
2) The user navigates directly to the page and no salesID is passed in the URL

Now to account for each situation above ->

1) If salesID IS NULL then get parameters from the page
2) If salesID IS NOT NULL then onload() display all relevant data for the salesID passed

I know how to write the query to load the page by default with a parameter, and I know how to load the page with parameters captured on the page from a button press event. What I do not know how to do is to combine the two and check multiple criteria. What I want to do is on pageload() evaluate criteria 1 - if a salesID is passed to the page, then go ahead and populate the page with all data for that salesID. If criteria 2 is true, then do not populate the page, wait for user input to select from select boxes and push the button.

This is basics of how I have the syntax for the page:

<?php
    //Capture variable from URL
    $salesID = urldecode($_GET['salesID']);

    //Check if variable is set
    if (isset($_GET['salesID'])) {
        //A salesID was passed to the page so load that data by default
        //ignoring any variables set on the page
    }
    else {
        if (isset($_POST['btnpressevent'])) {
            //button has been pressed capture variables from page and run query
        }
    }
?>

Out of curiousity, why don't you just populate the form with PHP then? — faerin
– faerin, Commented Sep 18, 2017 at 18:19

JSingh · Accepted Answer · 2017-09-18 18:30:16Z

1

You could try this:-

    // if salesId is not set or is null then show form with select and button

 if (!isset($_GET['salesId']) || is_null($_GET['salesId'])) {
      $html = "<form action='samepage.php'><select><option>Select one</option><option>Item 1</option></select><button name='btnpressevent'>Press button</button></form>";
      echo $html;
      return; // or die();
    }

    // do stuff with salesId
    echo "${$_GET['salesId']} helllo w";

answered Sep 18, 2017 at 18:30

JSingh

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1 Comment

mickmackusa Over a year ago

Please read about what isset() checks for. Your condition is too verbose.

Kinna T · Accepted Answer · 2017-09-18 18:29:11Z

0

You should change $salesID = urldecode($_GET['salesID']); to $salesID = to_utf8($_GET['salesID']);

and then simply if(isset($salesID) {}

GET is already decoded and you've already declared it as a variable.

I'm not sure exactly what you're asking beyond it generally not working, but those two changes should help it work as intended.

answered Sep 18, 2017 at 18:29

Kinna T

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