Fatal Error : call to undefined function , PHP

Question

I am working with php, and trying to call a function within a block of code, but I do not know why it causing the error that Uncaught Error: Call to undefined function GetUserIDFromUsername(), while it is defined later then.

The PHP Code

 if(isset($_GET["updateRow"])){
   
             $_fbURL  = $_GET["ajaxified"];
             
             if(!empty($_fbURL)){
                    $url = $_fbURL;
                    $urlParts = explode("facebook.com/", $url);
                    $username = GetUserIDFromUsername($urlParts[1]);



                function GetUserIDFromUsername($username) {
                    // For some reason, changing the user agent does expose the user's UID
                    $options  = array('http' => array('user_agent' => 'some_obscure_browser'));
                    $context  = stream_context_create($options);
                    $fbsite = file_get_contents('https://www.facebook.com/' . $username, false, $context);

                    // ID is exposed in some piece of JS code, so we'll just extract it
                    $fbIDPattern = '/\"entity_id\":\"(\d+)\"/';
                    if (!preg_match($fbIDPattern, $fbsite, $matches)) {
                        throw new Exception('Unofficial API is broken or user not found');
                    }
                    return $matches[1];
                }

                echo "My Id is : "." ".$username;

             } 
               
               
                    
           
           }

Are you sure you are parsing exact data from the URL? Be sure about the response. — AT-2017
– AT-2017, Commented Sep 16, 2017 at 7:43
when I try the same code just removing the isset method, then it returns the required data, you can try that on a simple php, providing your facebook url — Nadeem
– Nadeem, Commented Sep 16, 2017 at 7:44

Oyewole A. Samuel · Accepted Answer · 2017-09-16 07:46:16Z

2

Declare your method GetUserIDFromUsername($params) before calling it. You can move the method to the top of the caller.

answered Sep 16, 2017 at 7:46

Oyewole A. Samuel

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