Getting error while reading the file content using Python and Django

Question

I am trying to read the file content using URL and return that the content as response in html format but getting the following error:

 Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/exception.py", line 41, in inner
    response = get_response(request)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 187, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 185, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "/opt/lampp/htdocs/rework/Nuclear/RFI/secure/plant/views.py", line 217, in view_reactor
    pers = User.objects.get(pk=request.session['id'])
  File "/usr/local/lib/python2.7/dist-packages/django/contrib/sessions/backends/base.py", line 57, in __getitem__
    return self._session[key]
KeyError: u'id'

I am providing my code below:

site = 'http://127.0.0.1:8000/'
    my_list = []
    my_list.extend(['home', 'view_reactor'])
    if request.GET.get('file') is not None and request.GET.get('file') != '':
        file = request.GET.get('file')
        if file in my_list:
            full_path = site+file
            response = urllib.urlopen(full_path)
            lines = response.readlines()
            return HttpResponse(content=lines, content_type="text/html")
        else:
            return render(request, 'plant/home.html', {'count': 1})
    else:
        return render(request, 'plant/home.html', {'count': 1})


def view_reactor(request):
    """ This function for to get serch screen. """

    pers = User.objects.get(pk=request.session['id'])
    root = []
    user_name = pers.uname
    count = 1
    root.append(
        {'username': user_name,
         'count': count
         })
    return render(request, 'plant/view_reactor.html',
                  {'user': root, 'count': 1})

Here I am passing the the value in query string like this http://127.0.0.1:8000/createfile/?file=view_reactor and finally I need the response of http://127.0.0.1:8000/view_reactor page in html format. But in my code I am getting this error.

@arjun27 : I pasted my complete stack trace with required code. — satya
– satya, Commented Sep 11, 2017 at 6:18
your session dict does contains id "pk=request.session['id']" — Robert
– Robert, Commented Sep 11, 2017 at 6:20

Jahongir Rahmonov · Accepted Answer · 2017-09-11 06:26:40Z

1

The error is saying that there is no id key in your session dictionary. In the following line:

pers = User.objects.get(pk=request.session['id'])

And to me it looks redundant to get a user like this. You should be able to get a user simply by doing this:

pers = request.user

Provided that you have auth middleware installed.

Second option (not tested though):

pers = User.objects.get(pk=request.session['_auth_user_id'])

edited Sep 11, 2017 at 6:26

answered Sep 11, 2017 at 6:21

Jahongir Rahmonov

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7 Comments

satya Over a year ago

I did as per you but its throwing this AttributeError: 'AnonymousUser' object has no attribute 'uname' error.

Jahongir Rahmonov Over a year ago

@satya it means that the user was not authenticated before using this view. You should authenticate him when he logs in.

Jahongir Rahmonov Over a year ago

@satya please see the second option in my updated answer

satya Over a year ago

http://127.0.0.1:8000/view_reactor has the id in session because I can open this directly but here i am passing the same in query string and also content_type="text/plain" is working fine.

satya Over a year ago

No, its throwing this error Exception Value: u'_auth_user_id' . Actually after login i am setting the ID in session.

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