node.js - Sort JSON objects by a value [duplicate]

Question

I have this JSON file on my server:

{"1504929411112":{"name":"user1","score":"10"},"1504929416574":{"name":"2nduser","score":"14"},"1504929754610":{"name":"usr3","score":"99"},"1504929762722":{"name":"userfour","score":"40"},"1504929772310":{"name":"user5","score":"7"}}

Assuming I have parsed this file:

var json = JSON.parse(getJSONFile());

How can I now sort each object in the json variable by the score property? None of the array sorting functions work for me as json is not an array.

Object properties don't have any order, so you'll have to create an array if you want that data sorted. — Matt Gregory
– Matt Gregory, Commented Sep 9, 2017 at 4:26

Maciek Jurczyk · Accepted Answer · 2017-09-09 05:09:17Z

5

Since these are objects' properties, their order is usually unknown and not guaranteed. To sort them by some internal property, you would first have to change the Object into an Array, for example:

const json = JSON.parse(getJsonFile());

const jsonAsArray = Object.keys(json).map(function (key) {
  return json[key];
})
.sort(function (itemA, itemB) {
  return itemA.score < itemB.score;
});

For more, see:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/keys

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

edited Sep 9, 2017 at 5:09

answered Sep 9, 2017 at 4:30

Maciek Jurczyk

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1 Comment

user663031 Over a year ago

They are sorted by their keys automatically That's not exactly right. It's better to just say "their order is undefined".

Bharti Ladumor · Accepted Answer · 2017-09-09 05:19:32Z

3

var ob = { "fff": { "name": "user1", "score": "10" }, "bbbb": { "name": "user4", "score": "14" }, "dddd": { "name": "user2", "score": "99" }, "cccc": { "name": "user5", "score": "40" }, "aaaa": { "name": "user3", "score": "7" } };


Object.keys(ob).map(key => ({ key: key, value: ob[key] })).sort((first, second) => (first.value.name < second.value.name) ? -1 : (first.value.name > second.value.name) ? 1 : 0 ).forEach((sortedData) => console.log(JSON.stringify(sortedData)));

edited Sep 9, 2017 at 5:19

user663031

answered Sep 9, 2017 at 4:48

Bharti Ladumor

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1 Comment

user663031 Over a year ago

it's preferable to use localeCompare.

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