Transform string of objects into elements of object

Question

I have this below string of objects as shown below.

[0,5]
   0: "A123  G  2323232"
   1: "F345  G  345667"
   2: "T677  G  -34343"
   3: "G454  G  4343"
   4: ""

As you can see "A123 G 2323232" is a string which has tab seperated values in it.

I would like to have a final output as follows.

[0,4]
   0: 
     UserId:A123
     Type:  G
     Values: 2323232
   1: 
     UserId: F345  
     Type:  G
     Values: 345667
   2: 
     UserId: T677  
     Type:  G
     Values: -34343
   3: 
     UserId: G454  
     Type:  G
     Values: 4343

Please note. the 4th element is empty string. so it should not transform to final data.

Can anyone please suggest how to distribute this to different elements.

Separate your String using split() Function and then append that result to particular ID. — Maulik
– Maulik, Commented Aug 25, 2017 at 18:04
@MaulikBhatt- can you show me an example and i can have a look — Rihana
– Rihana, Commented Aug 25, 2017 at 18:05
Please define "tabs"! Are they two adjacent spaces ' '? Or are they \t? — ibrahim mahrir
– ibrahim mahrir, Commented Aug 25, 2017 at 18:12

Nina Scholz · Accepted Answer · 2017-08-25 18:09:31Z

3

You could match non space parts and deconstruct the array to the wanted properties and return an object.

var data = ["A123  G  2323232", "F345  G  345667", "T677  G  -34343", "G454  G  4343", ""],
    result = data
        .filter(Boolean)
        .map(s => {
            var [UserId, Type, Values] = s.match(/[^ ]+/g);
            return { UserId, Type, Values };
        });
                
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Aug 25, 2017 at 18:09

Nina Scholz

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mhodges · Accepted Answer · 2017-08-25 18:14:02Z

3

You can split each string into its individual pieces of data, and then map those pieces into an object with the properties you want. Here's what it would look like:

var data = ["A123  G  2323232","F345  G  345667","T677  G  -34343","G454  G  4343", ""];
/* ES6 Syntax */
var objects = data.filter(str => str !== "").map(function (str) {
  var [UserId, Type, Values] = str.split("  ");
  return { UserId, Type, Values };
});

/* ES5 Syntax */
var objectsES5 = data.filter(function (str) {
  return str !== "";
}).map(function (str) {
  var split = str.split("  ");
  return {
    UserId: split[0],
    Type: split[1],
    Values: split[2]
  };
});

console.log(objects);

edited Aug 25, 2017 at 18:14

answered Aug 25, 2017 at 18:06

mhodges

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2 Comments

ibrahim mahrir Over a year ago

map won't work. What about the empty string at the end of the original array.

mhodges Over a year ago

@ibrahimmahrir missed that, thanks. Nina's solution adds that with .filter(Boolean). That's probably the best way to do it, but for the sake of not copying her idea, I will filter on empty string.

ibrahim mahrir · Accepted Answer · 2017-08-25 18:07:16Z

1

Use a combo of reduce and split:

var strings = [
  "A123	G	2323232",
  "F345	G	345667",
  "T677	G	-34343",
  "G454	G	4343",
  ""
];

var result = strings.reduce(function(res, str) {  // for each string in strings arrays
  var parts = str.split("\t");                    // split the string by tabs
  if(parts.length === 3) {                        // if the string is valid (the splitting yielded 3 parts)
    res.push({                                    // then add an object to the result array using the parts we got
      UserID: parts[0],
      Type: parts[1],
      Values: parts[2]
    });
  }
  return res;
}, []);

console.log(result);

edited Aug 25, 2017 at 18:07

answered Aug 25, 2017 at 18:05

ibrahim mahrir

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1 Comment

ibrahim mahrir Over a year ago

@Rihana I hard copied your strings that didn't have tabs \t in them. Fixed.

Ibrahim Khan · Accepted Answer · 2017-08-25 18:08:31Z

1

You can do it using javascript filter() and map() methods like following.

var array = ["A123  G  2323232",
             "F345  G  345667",
             "T677  G  -34343",
             "G454  G  4343",
             ""];

var result = array.filter(function(item) {
  return item.trim();
}).map(function(item) {
  var split = item.split('  ');
  
  return {
    UserId: split[0],
    Type: split[1],
    Values: split[2]
  };
});

console.log(result);

answered Aug 25, 2017 at 18:08

Ibrahim Khan

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