Searching array with multiple keys

Question

I can see this works fine for searching a simple array:

var arr1 = ['a','b','c','d','e'];
var index1 = arr1.indexOf('d');
console.log("index1:" + index1); // index1:3

When I try to do the same thing for a different kind of array, it doesn't find the "jane" value:

var arr2 = [{"id":0,"name":"petty"},{"id":1,"name":"jane"},{"id":2,"name":"with"}];
var index2 = arr2.indexOf('jane');
console.log("index2:" + index2); // index2:-1

Sorry - I realise I am probably missing something obvious. I have searched on SO / google for searching multi dimensional arrays, but I don't even know if the array in the 2nd example is a 2d / multi dimensional array, so I am probably not searching for the right thing.

Possible duplicate of How to get index of object by its property in javascript — Peter B
– Peter B, Commented Aug 22, 2017 at 10:58
arr2 is not multi dimensional array but it is array of objects, notice the {}, it means object. — Hassan Imam
– Hassan Imam, Commented Aug 22, 2017 at 10:59

Nenad Vracar · Accepted Answer · 2017-08-22 10:58:14Z

1

You can use findIndex() method to find index of object with specific value.

var arr = [{"id":0,"name":"petty"},{"id":1,"name":"jane"},{"id":2,"name":"with"}];

var index = arr.findIndex(e => e.name == 'jane')
console.log("index: " + index);

answered Aug 22, 2017 at 10:58

Nenad Vracar

122k16 gold badges160 silver badges184 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Peter B Over a year ago

I'd like to note that findIndex was added only in ECMAScript 2015, and it is not compatible with some browsers (esp. Internet Explorer). See developer.mozilla.org/en/docs/Web/JavaScript/Reference/…

lukaleli · Accepted Answer · 2017-08-22 10:59:33Z

0

First of all: it's not a multi-dimensional array. It's an array consisting of objects. It's one-dimensional. To find an object you need to iterate through an array and check the needed key, e.g.:

arr.findIndex(function(el) { return el.name === 'jane' })

answered Aug 22, 2017 at 10:59

lukaleli

3,6653 gold badges25 silver badges32 bronze badges

Comments

Nina Scholz · Accepted Answer · 2017-08-22 11:00:07Z

0

You could check all values of the objects and use Array#findIndex instead of Array#indexOf.

var arr2 = [{ id: 0, name: "petty" }, { id: 1, name: "jane" }, { id: 2, name: "with" }],
    index2 = arr2.findIndex(o => Object.values(o).some(v => v === 'jane'));

console.log(index2);

answered Aug 22, 2017 at 11:00

Nina Scholz

388k26 gold badges367 silver badges417 bronze badges

3 Comments

Jonas Libbrecht Over a year ago

Nested iterators/generators seem pretty inefficient, as Nenad already posted. This will be better: arr.findIndex(e => e.name == 'jane')

Nina Scholz Over a year ago

@JonasLibbrecht, right, but only if you know the key in advance.

Jonas Libbrecht Over a year ago

@ Nina Scholz, that's correct but then you are performing a needle in a haystack search and that's basically inefficient on it's own and should not be implemented like this. That issue would be better solved with binary trees or something else.

Vinod kumar G · Accepted Answer · 2017-08-22 11:07:51Z

0

var arr = [{"id":0,"name":"petty"},{"id":1,"name":"jane"},{"id":2,"name":"with"}];
arr.findIndex((item)=>{return item.name=="petty"})
//output is 0

answered Aug 22, 2017 at 11:07

Vinod kumar G

6657 silver badges17 bronze badges

Collectives™ on Stack Overflow

Searching array with multiple keys

4 Answers 4

1 Comment

Comments

3 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

1 Comment

Comments

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related