Call JS function inside PHP code

Question

I have a foreach loop that generates an input with type of checkbox with items (from DB). Right now, there is no default checkbox that is checked and every time a user checks the checkbox it calls to JS function.

Now, the clients wants me to check the first checkbox by default. I know how to check it but how do I call the JS function by default?

This is my HTML - the update_addon() is JS func.

<? foreach ($pros as $pro):?>
    <label class="checkbox text-left">
        <input type="checkbox" name="checkbox" 
         onchange="update_addon(<?=$pro['id']?>,this)">
         <?=$pro['name']?> ( <?=$pro['price']?> )
    </label>
<? endforeach; ?>

The update_addon() is an AJAX call.

Sanan Guliyev · Accepted Answer · 2017-08-16 13:38:18Z

1

You have a syntax problem. You must put question mark on this part "<?=$pro['id']>".

 <? foreach ($pros as $pro):?>
     <label class="checkbox text-left">
         <input type="checkbox" name="checkbox" 
          onchange="update_addon(<?=$pro['id']?>,this)">
          <?=$pro['name']?> ( <?=$pro['price']?> )
      </label>
  <? endforeach; ?>

edited Aug 16, 2017 at 13:38

answered Aug 16, 2017 at 13:36

Sanan Guliyev

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2 Comments

Sagar V Over a year ago

while the code may solve the problem, update this answer with required details like where is the problem, what is the problem, etc.

user6247099 Over a year ago

It is just copy-past. The code works fine, now I need to change it a bit to fit the new situation

user6247099 · Accepted Answer · 2017-08-16 14:07:15Z

0

Finally, I did it. did a click() event on js file to click the first checkbox. thanx

answered Aug 16, 2017 at 14:07

user6247099

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