Sorting JSONarray by nested property

Question

I am trying to sort array of JSON values, but the property to sort is nested within the JSON object. For this example the sort is to be done using data.nested-name.

I tried using https://stackoverflow.com/a/8175221/2053159 but without any success.

[
{
name: 'a75',
data: {nested-name:"zz\, Hello// There="}},
{
name: 'z32',
data: {nested-name:"aa\, Hello// There="}},
];

expected output ->

[
{
name: 'a75',
data: {nested-name:"aa\, Hello There="}},
{
name: 'z32',
data: {nested-name:"zz\, Hello There="}},
];

Nested name do contain lot of back and forward slashes and other special characters. I don't use external libraries, please provide solutions using native JavaScript.

use data['nested-name']

Jaromanda X
– Jaromanda X

2017-08-16 00:21:53 +00:00
Commented Aug 16, 2017 at 0:21 — Jaromanda X
– Jaromanda X, Commented Aug 16, 2017 at 0:21

marc_s · Accepted Answer · 2021-02-09 05:38:58Z

4

Assuming arr is your array, you can sort like so:

arr.sort( ( a, b ) => a.data[ "nested-name" ] > b.data[ "nested-name" ] )

For higher string comparison accuracy you can use localeCompare

arr.sort( ( a, b ) => a.data[ "nested-name" ].localeCompare(b.data[ "nested-name" ]) )

edited Feb 9, 2021 at 5:38

marc_s

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answered Aug 16, 2017 at 0:21

vox

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3 Comments

NewBee Over a year ago

How can i ignore case sensitivity?

Alex Kudryashev Over a year ago

@NewBee add toLowerCase()

Jaromanda X Over a year ago

=> a.data["nested-name"].toLowerCase() > b.data[ "nested-name" ].toLowerCase() - or use => a.data["nested-name"].localeCompare(b.data["nested-name"])

Alex Kudryashev · Accepted Answer · 2017-08-16 00:33:45Z

1

array.sort function takes an optional argument function(a,b) which must return -1, 0, or 1 depending on comparison.
Your data definition contains an error nested-name:"zz\, Hello// There=". If you use - then you must quote the name.
Working sample is here.

var arr=[
{
name: 'a75',
data: {'nested-name':"zz\, Hello// There="}},
{
name: 'z32',
data: {'nested-name':"aa\, Hello// There="}},
];

var result=arr.sort(function(a,b){
  return a.data["nested-name"] > b.data["nested-name"];
  });
  console.log(result);

answered Aug 16, 2017 at 0:33

Alex Kudryashev

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1 Comment

NewBee Over a year ago

How can i ignore case sensitivity?

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