Comparison in empty array and null in powershell

Question

Code:

$arr=@() 
if($arr -ne $null){"NE"} else{"E"} 
if($null -ne $arr){"NE"} else{"E"}

Output:

E
NE

How is this possible ?

The above scenario changes when you use -eq instead of -ne! This is indeed very curious. Please include this when considering your answers. Result: "E", "E" — Banoona
– Banoona, Commented Aug 24, 2018 at 8:06

woxxom · Accepted Answer · 2017-07-26 12:00:07Z

6

The first if compares each element of the array to $null and produces a collection of non-null elements, which in your case is empty, thus it's false and else displays E.

The second if compares a single object $null with another object $arr and since $arr itself is not $null (as an object that stores an empty collection inside) it displays NE.

answered Jul 26, 2017 at 12:00

woxxom

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