Convert one JSON structure to another using Json.Net

Question

Input JSON:

{
    "name" : "objname",
    "abc" : 1,
    "def" : 2
}

Desired output JSON:

{
    "objname" :
    {
        "abc" : 1,
        "def" : 2 
    }
}

I tried as shown below, but I feel it's not the correct way.

// This is the class object
public class Obj
{
    public string Name { get;set;}
    public string abc { get; set; }
    public string def { get; set; }
}         

var obj = JsonConvert.DeserializeObject<Obj>(json);

StringBuilder sb = new StringBuilder();
sb.Append(" { ");
sb.AppendLine(obj.Name);
sb.AppendLine(" :  {");
sb.AppendLine(GetMemberName(() => obj.abc) + ":" + obj.abc + ",");
sb.AppendLine(GetMemberName(() => obj.def) + ":" + obj.abc);
sb.AppendLine(" :  }");

1) Your desired output "objname" : { "abc" : 1, "def" : 2 } isn't even JSON, it's missing the outer { and }. 2) What have you tried so far? — dbc
– dbc, Commented Jul 22, 2017 at 5:49
Look at the homepage for this package. newtonsoft.com/json. You will see a Serialize and DeserializeObject. That's what you need. And please try before asking here. — Aamir Mulla
– Aamir Mulla, Commented Jul 22, 2017 at 5:50
@GarrGodfrey: No, JSON doesn't have to start with { or [. It's perfectly valid to have a JSON document which is just a string, null token or number for example. But yes, for an object, you do need the braces. — Jon Skeet
– Jon Skeet, Commented Jul 22, 2017 at 7:15

Geoduck · Accepted Answer · 2017-07-22 07:44:59Z

2

The first step is deserializing. You can just go to a dictionary:

Dictionary<string, string> dict = 
    JsonConvert.DeserializeObject<Dictionary<string, object>>(json);

Then, to get it back, you probably need to use a dictionary as well. You cannot use a predefined (even compiler generated) class, since you don't know the property name.

String name = (string)dict["name"];
// remove name from dictionary
dict.Remove(name);
var output = 
   new Dictionary<string,object>() {{name, dict}};

Then, save it back out:

string json = JsonConvert.SerializeObject(output);

edited Jul 22, 2017 at 7:44

answered Jul 22, 2017 at 7:28

Geoduck

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5 Comments

Sir Rufo Over a year ago

That will not produce the requested output => .net fiddle

Sir Rufo Over a year ago

You will have to deserialize to a Dictionary<string,object> instead => .net fiddle

Geoduck Over a year ago

yep, typo. fixing

Geoduck Over a year ago

yeah, saw your fiddle. I was intended as a guide, not ready to go

Raghu Over a year ago

@GarrGodfrey Thanks a lot. Its working. I was not knowing how to leverage dictionary.

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