How to find all matching keys and values of one object in array of objects?

Question

I need a code which would loop through an array of objects and check if keys and values match with ones in a separate object, and then push object that contains all keys and values in a new array, so for a specific case:

var arr = [{name: 'john', lastname: 'roberts', children: 3},
           {name: 'john', lastname: 'green', children: null}, 
           {name: 'steve', lastname: 'baker', children: 3}];

var obj = {name: 'john', children: 3};

result would be:

arr2 = [{name: 'john', lastname: 'roberts', children: 3}];

Jarek Kulikowski · Accepted Answer · 2017-07-20 02:25:33Z

2

expanding @Psidom version

var arr = [{name: 'john', lastname: 'roberts', children: 3},
           {name: 'john', lastname: 'green', children: null}, 
           {name: 'steve', lastname: 'baker', children: 3}];

var obj = {name: 'john', children: 3};

console.log(
  arr.filter(x => Object.keys(obj).every( k => x[k] == obj[k]))
);

answered Jul 20, 2017 at 2:25

Jarek Kulikowski

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Comments

akuiper · Accepted Answer · 2017-07-20 02:12:36Z

1

Use filter on the Array:

var arr = [{name: 'john', lastname: 'roberts', children: 3},
           {name: 'john', lastname: 'green', children: null}, 
           {name: 'steve', lastname: 'baker', children: 3}];

var obj = {name: 'john', children: 3};

console.log(
  arr.filter(x => x.name === obj.name && x.children === obj.children)
);

answered Jul 20, 2017 at 2:12

akuiper

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4 Comments

I J Over a year ago

But what if I don't know keys or have another array of objects with different key names?

akuiper Over a year ago

Can you give an example? Do the keys in the obj always exist in the keys of objects in the array?

I J Over a year ago

Yes, in first example we had name, children keys in another we'd have age, height, weight or whatever (in both array and obj). So I can't use key names, I rather need a universal solution for both cases.

akuiper Over a year ago

I think @JarekKulikowski 's answer is what you need.

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