JSON.parse not working for changing a string into an object

Question

I have a string

{ city : Chicago , country : us , name : Somebody , plan : quarter90wtrial },{ city : New York , country : us , name : Somebody , plan : quarter90wtrial },{ city : Portland , country : us , name : Somebody , plan : quarter90wtrial },{ city :null, country :null, name : Somebody , plan : quarter90wtrial },{ city : Mexico City , country : mx , name : Aaron , plan : quarter90wtrial },{ city : Boston , country : us , name : Somebody , plan : quarter90wtrial },{ city : Los Angeles , country : us , name : Somebody , plan : quarter90wtrial },{ city : London , country : gb , name : Aaron , plan : quarter90wtrial },{ city : Los Angeles , country : us , name : Aaron , plan : quarter90wtrial },{ city : Chicago , country : us , name : Aaron , plan : quarter90wtrial }

What I am trying to do is turn this string into an object where I can iterate and print out the city, country, and name for each one. So far I have figured out how to split the string to print out each line individually.

str = str.split('},{');
for(var i =0; i < str.length; i++)
{
      alert(str[i]);
}

What I cannot figure out is how to convert the string to an object where I can print out the city, country, name, etc.

What you posted is not valid JSON, so you cannot use JSON.parse. What creates this string? Any chance you make it produce JSON? That would be the best solution. — Felix Kling
– Felix Kling, Commented Jul 19, 2017 at 18:30
From what I assume, your string is missing the enclosing [] without which it is not valid json — Shubham Khatri
– Shubham Khatri, Commented Jul 19, 2017 at 18:32
@ShubhamKhatri It's also missing a ton of double quotes around all the properties and values... — War10ck
– War10ck, Commented Jul 19, 2017 at 18:32
When producing JSON, you may want to use a validator such as jsonlint.com to validate whether the JSON that was created by your program is syntactically correct. — War10ck
– War10ck, Commented Jul 19, 2017 at 18:33
If you can generate correctly formatted JSON, this becomes entirely easy. As @FelixKling asked, what is generating the string above? — War10ck
– War10ck, Commented Jul 19, 2017 at 18:40

Washington Guedes · Accepted Answer · 2017-07-19 18:39:23Z

You had the correct initial idea.

However, after the split method, you will still need to map every pair of key:value like this:

var str = '{ city : Chicago , country : us , name : Somebody , plan : quarter90wtrial },{ city : New York , country : us , name : Somebody , plan : quarter90wtrial },{ city : Portland , country : us , name : Somebody , plan : quarter90wtrial },{ city :null, country :null, name : Somebody , plan : quarter90wtrial },{ city : Mexico City , country : mx , name : Aaron , plan : quarter90wtrial },{ city : Boston , country : us , name : Somebody , plan : quarter90wtrial },{ city : Los Angeles , country : us , name : Somebody , plan : quarter90wtrial },{ city : London , country : gb , name : Aaron , plan : quarter90wtrial },{ city : Los Angeles , country : us , name : Aaron , plan : quarter90wtrial },{ city : Chicago , country : us , name : Aaron , plan : quarter90wtrial }';

var result = str.split('},{').map(function(itemStr) {
    var itemObj = {};

    // here we map each "key:value" pair
    itemStr.replace(/.*?(\w+) *: *(.*?) *[,}]/g, function(match, key, val) {
        itemObj[key] = val;
    });
    return itemObj;
});

console.log(result)

You can see how the regular expression is working here: https://regex101.com/r/E5tg26/1

Hope it helps.

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