How do add fill an html dropdown list by items in an array in php

Question

This is the HTML in a php file.

<select id="efHidden" style="width:80px;" class="text ui-widget-content ui-corner-all">
     <option value="0">off</option>
     <option value="1">on</option>
</select>

and I have a php variable $arr having the required values to be shown

It is all these smaller things that .Net does for you that are the hard part in the transition from .Net to PHP. Keep at it. :) — DampeS8N
– DampeS8N, Commented Dec 22, 2010 at 12:23

piddl0r · Accepted Answer · 2010-12-22 12:15:54Z

1

<?php $arr = array('off' => 0, 'on' => 1); ?>

<select>
    <?php 
       foreach($arr as $k => $v)
       {
           echo "<option value=\"$v\">$k</option>";
       }
    ?>
</select>

answered Dec 22, 2010 at 12:15

piddl0r

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Comments

Bhanu Prakash Pandey · Accepted Answer · 2010-12-22 12:13:17Z

1

<?php
$arr = array('0' => 'off', '1' => 'on');
?>
<select id="efHidden" style="width:80px;" class="text ui-widget-content ui-corner-all">
                        <?php foreach ($arr as $key=>$value) {?>
                        <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
                        <?php } ?>
                       </select>

answered Dec 22, 2010 at 12:13

Bhanu Prakash Pandey

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Comments

user549167 · Accepted Answer · 2010-12-22 12:08:05Z

0

$arr = array('1' => 'Option One', '2' => 'Option Two', '3' => 'Option Three');
foreach($arr as &$item){ echo '<option value="'.$item[0].'">'.$item[1].'</option>'; }

answered Dec 22, 2010 at 12:08

user549167

1 Comment

John Carter Over a year ago

-1 - $item will be a string, not an array, and also there's no need to access $item by reference.

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