Call webservice through javascript?

Question

I have an web service running on http://remoteip:8080/TestService I want to call it through java script this service takes parameters in JSON format {"status":"F","subscriber":[{"PhoneNumber": 1234567890}, {"PhoneNumber":0123456789}]} like this how can I implement this in javascript.

Rahul Mahadik · Accepted Answer · 2017-06-20 05:08:49Z

1

<script>
function callWebService() {

            jQuery.ajax({
                url: 'http://remoteip:8080/TestService',
                type: "POST",
                data: {
                    "status": "F",
                    "PhoneNumber":"0123456789",
                    .....
                    .....
                },
                dataType: 'json',
                success: function (data) {
                    console.dir(data);
                },
                error: function (xhr, err) {
                    alert("readyState: "+xhr.readyState+"\nstatus: "+xhr.status);
                    alert("responseText: "+xhr.responseText);
                },
                complete: function () {
                }
            });      
    }

</script>

Hope it helps you

answered Jun 20, 2017 at 5:08

Rahul Mahadik

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6 Comments

Akshay Patil Over a year ago

Second parameter expects array of phone numbers can you help me with this?

Rahul Mahadik Over a year ago

Create array of phone numbers and pass array object to "PhoneNumber": phoneNumberArray

Akshay Patil Over a year ago

can you help me with syntax

Rahul Mahadik Over a year ago

var phoneNumbers = [1234567890, 0123456789]; var phoneNumbersJson = JSON.stringify(phoneNumbers); data:{ PhoneNumber: phoneNumbersJson }

Akshay Patil Over a year ago

var phoneNumbers = [1234567890, 0123456789];  				var phoneNumbersJson = JSON.stringify(phoneNumbers);                  url: 'http://104.155.141.228:8080/updatesubscriber_status',                 type: "POST",                 data: {                     "status": "F",                     "PhoneNumber":"phoneNumbersJson"                 },

Is this correct

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