Morning, I'm trying to display a div onmouseover. I created a function but i don't know what is wrong. Could you help me please.
The HTML code:
<!DOCTYPE html>
<html lang="it">
<head>
<meta charset="utf-8">
<title> PHOTOGALLERY</title>
<link rel="stylesheet" href="style.css" type="text/css"/>
<link rel="stylesheet" href="css/smoothness/jquery-ui-
1.9.2.custom.css"/>
<script type="text/javascript" src="js/jquery-3.2.1.min.js"></script>
<script src="http://malsup.github.com/jquery.cycle2.js"></script>
<script type="text/javascript" src="js/jquery-ui-1.9.2.custom.js">
</script>
<script>
function show_img_container() {
$("#image_container").css("display", "block");
}
</script>
</head>
<body>
<div id="div_container">
<div id="div_image" class="cycle-slideshow">
<img src="images/2.jpg" style="height:100%; width:100%">
<img src="images/3.jpg" style="height:100%; width:100%">
<img src="images/4.jpg" style="height:100%; width:100%">
<img src="images/5.jpg" style="height:100%; width:100%">
</div>
<div id="image_container" onmouseover="show_img_container()"></div>
</div>
</body>
</html>
In the css file i have a image_container id where the attribute display is set to 'none';