why isn't this javascript regex split function working?

Question

I'm trying to split a string by either three or more pound signs or three or more spaces.

I'm using a function that looks like this:

     var produktDaten = dataMatch[0].replace(/\x03/g, '').trim().split('/[#\s]/{3,}');  
     console.log(produktDaten + ' is the data');

I need to clean the data up a bit, hence the replace and trim.

The output I'm getting looks like this:

##########################################################################MA-KF6###Beckhoff###EL1808    BECK.EL1808###MA-KF7###Beckhoff###EL1808    BECK.EL1808###MA-KF12###Beckhoff###EL1808    BECK.EL1808###MA-KF13###Beckhoff###EL1808    BECK.EL1808###MA-KF14###Beckhoff###EL1808    BECK.EL1808###MA-KF15###Beckhoff###EL1808    BECK.EL1808###MA-KF16###Beckhoff###EL1808    BECK.EL1808###MA-KF19###Beckhoff###EL1808    BECK.EL1808 is the data

How is this possible? Irrespective of the input, shouldn't the pound and multiple spaces be deleted by the split?

No, because you did not pass a regex. It should be .split(/[#\s]{3,}/). Are you seeking this output? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jun 6, 2017 at 13:21
"either three or more pound signs or three or more spaces" then your regex should be /#{3,}|\s{3,}/. Your current regex would also split this "one## ##two" -> ['one', 'two'] — Thomas
– Thomas, Commented Jun 6, 2017 at 14:21

Wiktor Stribiżew · Accepted Answer · 2017-06-06 13:25:51Z

You passed a string to the split, the input string does not contain that string. I think you wanted to use

/[#\s]{3,}/

like here:

var produktDaten = "##########################################################################MA-KF6###Beckhoff###EL1808    BECK.EL1808###MA-KF7###Beckhoff###EL1808    BECK.EL1808###MA-KF12###Beckhoff###EL1808    BECK.EL1808###MA-KF13###Beckhoff###EL1808    BECK.EL1808###MA-KF14###Beckhoff###EL1808    BECK.EL1808###MA-KF15###Beckhoff###EL1808    BECK.EL1808###MA-KF16###Beckhoff###EL1808    BECK.EL1808###MA-KF19###Beckhoff###EL1808    BECK.EL1808";
console.log(produktDaten.replace(/\x03/g, '').trim().split(/[#\s]{3,}/));

This /[#\s]{3,}/ regex matches 3 or more chars that are either # or whitespace.

NOTE: just removing ' around it won't fix the issue since you are using an unescaped / and quantify it. You actually need to quantify the character class, [#\s].

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