python 'float' object cannot be interpreted as an integer

Question

import numpy as np
def romberg(f,l):
    val=np.zeros(l)
    for i in range(0,l):
        h=2**(1-i)
        N=2/h
        val[i]=trapez(f,h,N)
    return val

def trapez(f,h,N):
    result=0                     
    stuetz=np.zeros(N+1);
    for j in range(0,N+1):
        stuetz[j]=0+j/N                  
    sum=0
    for k in range(1,N):                 #bilde summe von 1-N-1
        sum+=np.polyval(f,stuetz[k])
    a=np.polyval(f,0)*0.5*h
    b=(np.polyval(f,stuetz[N]))*0.5*h
    result=a+(h*sum)+b
    return result

main:

p=[1,0,0]
romberg(p,5)

error:

----> 3 romberg(p,5)

----> 7         val[i]=trapez(f,h,N)

TypeError: 'float' object cannot be interpreted as an integer

how can i fix this please help me? i appreciate it!

N=int(2/h) in your first function You need N to be an integer to be use in range(), so you have to explicitely tell the program you want N to be an integer. — Nuageux
– Nuageux, Commented May 29, 2017 at 10:06

Szabolcs Dombi · Accepted Answer · 2017-05-29 10:53:16Z

8

change N=2/h to N=2//h to perform integer division.

def romberg(f,l):
    val=np.zeros(l)
    for i in range(0,l):
        h=2**(1-i)
        N=2//h
        val[i]=trapez(f,h,N)
    return val

edit:

You can also use int(2/h)

def romberg(f,l):
    val=np.zeros(l)
    for i in range(0,l):
        h=2**(1-i)
        N=int(2/h)
        val[i]=trapez(f,h,N)
    return val

answered May 29, 2017 at 10:53

Szabolcs Dombi

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