No pointer decay during assignment to pointer-to-fixed array

I've recently discovered the syntax for pointers to fixed arrays. While experimenting with it, I was surprised to see that pointer decay didn't seem to work as in the below example:

#include <iostream>

int main( int argc, char* argv[] )
{
  char pa[3];
  //char (*parr)[3] = &pa; // This works.
  char (*parr)[3] = pa;    // This doesn't work - why?
  std::cout << (void*)pa << std::endl;
  std::cout << (void*)parr << std::endl;
  return 0;
}

Output:

prog.cpp: In function 'int main(int, char**)':
prog.cpp:10:21: error: cannot convert 'char*' to 'char (*)[3]' in initialization
char (*parr)[3] = pa;
       ^

Compilation performed with gcc-4.9.2 (Code Chef).

Can someone please help identify what is wrong here?

Update:

This is an interesting but even more puzzling finding: the pointer decay works as expected if compiling C-style (I selected "C" as the compiler in Code Chef, although it still shows gcc-4.9.2. Perhaps there are different compiler flags being passed to differentiate between C and C++ compilation.)

The C version of the above code:

#include <stdio.h>

int main( int argc, char* argv[] )
{
  char pa[3];
  /* char (*parr)[3] = &pa; */
  char (*parr)[3] = pa;
  printf( "0x%x\n", pa);
  printf( "0x%x\n", parr);
  return 0;
}

Output from the compiled C code:

0xbf92b1fd
0xbf92b1fd