I am running below command on Bash prompt:
bash-3.2$ x=12
bash-3.2$ echo $x
12
bash-3.2$ perl -e '$age=$x; print "Age = $age\n"'
Age =
bash-3.2$
I am not getting the age/number printed..! How shall i import my unix bash variable inside my perl command..!?
First you have to export x in the shell. Then you can access the variable from Perl as $ENV{x}.
$ x=12
$ export x
$ perl -e '$age=$ENV{x}; print "Age = $age\n"'
Age = 12
This answer on this thread accesses the variable directly through the environment, which seems like a neater way.
Still, to demonstrate a way to use direct shell substitution (which has it's uses), then the right way to do it would be like this:
perl -e '$age='"$x"'; print "Age = $age\n"'
perl sees this as it's input: perl -e $age=12; print "Age = $age\n"The single quotes for the -e parameter prevents the shell variable from being expanded. Use $ENV{'myvar'} to get the value of shell variable $myvar
And export the variable too as noted by the other answer.
