In the following string how to get the id after the directory media and after getting the id ignore the rest of the string to read only the id numbers
id_arr= ["/opt/media/12/htmls","/opt/media/24/htmls","/opt/media/26/htmls","/opt/media/56/htmls"]
The output should be 12 24 26 56
If the strings always look the way you said, try
ids = [int(s.split("/")[3]) for s in id_arr]
os.path.sep instead of a plain /, just in case?
>>> import re
>>> myre = re.compile("^.*/media/(\d+)")
>>> for item in id_arr:
... print (myre.search(item).group(1))
...
12
24
26
56
media directory. No other solution considers the possibility that it might not be the third field (not even Puller's, since it assumes the prefix is /opt/media).[x.split('/')[3] for x in id_arr]
The correct way probably involves some clever use of the os.path module, but for the input given, just use a regex for media\/([0-9]+) and extract the first group.
parts = "/opt/media/12/htmls","/opt/media/24/htmls","/opt/media/26/htmls","/opt/media/56/htmls"
for str in parts:
print str.split("/")[3]
EDIT: unuseful rpartition() removed
