Hyperlink in a PHP output table

Question

I am trying to create an output table in PHP after extracting data from a database. The fourth column needs to be a hyperlink. I have used the following code. But I am getting error in regards to the hyperlink section. Could you please let me know how to rectify it?

Thanks!

 echo"<tr>
            <td>".$row["name"]."</td>
            <td>".$row["age"]."</td>
            <td>".$row["sex"]."</td>                                                                                                                                                                        
            <td><a href= "https://weblink.com/path1/path2/test.php?name='.urlencode($row["name"]).'&age='.urlencode($row["age"]).'">Click for next</a></td>

  </tr>";

You need to escape the quotes, \" inside the string, the quotes that surrounds the link. — Qirel
– Qirel, Commented May 9, 2017 at 20:37
And you need to end the string with the same quote you started it with. You started with double quotes, but then ended with single quotes before .urlencode — Barmar
– Barmar, Commented May 9, 2017 at 20:45

jrn · Accepted Answer · 2017-05-10 13:03:39Z

1

Looking at your forth <td> your code is attempting to end the echo after href=", hence you have to escape the quotation mark href=\". If this looks too ugly you can also use single quotes instead.

echo"<tr>
        <td>".$row["name"]."</td>
        <td>".$row["age"]."</td>
        <td>".$row["sex"]."</td>                                                                                                                                                                        
        <td><a href=\"https://weblink.com/path1/path2/test.php?name=".urlencode($row["name"])."&age=".urlencode($row["age"])."\">Click for next</a></td>
</tr>";

edited May 10, 2017 at 13:03

answered May 9, 2017 at 20:48

jrn

2,8205 gold badges32 silver badges56 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Qirel Over a year ago

A good answer contains a description what was changed, not just "try this". What did you change, and why? Although it might be obvious to some, its better to include a description of the issue.

jrn Over a year ago

I agree very much. Since I was short on time and there was no answer yet I figured it would help @dash to have some working code at least. I absolutely agree with you though that a good answer should include an explanation :-)

Mike Casan Ballester · Accepted Answer · 2017-05-09 21:43:29Z

0

I started php not long ago and I realized that it can be useful to format your code differently for clarity. Try using your tags differently if you can, for exemple:

// end php and switch to html 
?> 

    <tr>
       <td><?php echo $row["name"]; ?></td>
       <td><?php echo $row["age"]; ?></td>
       <td><?php echo $row["sex"]; ?></td>                                                                                                                                                                        
       <td><a href= "https://weblink.com/path1/path2/test.php?name=<?php echo urlencode($row["name"]); ?>&age=<?php echo urlencode($row["age"]); ?>">Click for next</a></td>
    </tr>

    <?php // resume php

answered May 9, 2017 at 21:43

Mike Casan Ballester

1,77021 silver badges35 bronze badges

Collectives™ on Stack Overflow

Hyperlink in a PHP output table

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related