Delete single element in dynamic array C++ [duplicate]

Question

I'm making an array of strings, with 100 elements. I created the array in my .h file:

const int N = 100;

typedef struct {
int size = 0;
string *list = new string[N];
} tStringList;

Then in my .cpp file, I implement the functions insert, search, remove and print for the array. But I don't know how to delete the element at the position pos of the array in the function remove. I tried this but it gives me error:

void remove(tStringList & stringList, int pos){

delete stringList.list[pos];
stringList.size--;
}

How do I delete a single element in a dynamic array?

this is not possible. new and delete in C++ ist not recommendet, use containers like std::vector. — The Techel
– The Techel, Commented Apr 28, 2017 at 8:42
You need to move the elements from pos + 1 till N to one previous position in the array. — CinCout
– CinCout, Commented Apr 28, 2017 at 8:43
I picked one of the many duplicates at random. Also see this list. — Cody Gray
– Cody Gray ♦, Commented Apr 28, 2017 at 8:45

Luca Di Liello · Accepted Answer · 2017-04-28 11:50:48Z

1

You have not to delete the element at pos, you should only move all elements after pos back with something like this:

void remove(tStringList & stringList, int pos){
    if(pos < stringList.size && pos >= 0){
        for(int i = pos; i < stringList.size - 1; i++){
            stringList.list[i] = stringList.list[i+1];
        }
        stringList.size--;
    }
}

edited Apr 28, 2017 at 11:50

answered Apr 28, 2017 at 8:47

Luca Di Liello

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1 Comment

Luca Di Liello Over a year ago

I edited the answer with size and pos check.

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