I have these 3 strings:
YELLOW,SMALL,STRETCH,ADULT,T21fdsfdsfs
YELLOW,SMALL,STRETCH,ADULT,Tdsfs
YELLOW,SMALL,STRETCH,ADULT,TD
I would like to remove everything after the last , including the comma. So i want to remove these parts ,T21fdsfdsfs, ,Tdsfs and TD. How could i do that in Python?
You can't. Create a new string with the pieces you want to keep.
','.join(s.split(',')[:4])
s.rsplit(',', 1)[0]
Anyway, I suggest having a look at Ignacio Vazquez-Abrams's answer too, it might make more sense for your problem.
According to The Zen of Python:
There should be one-- and preferably only one --obvious way to do it.
...so here's a third, which uses rpartition:
>>> for item in catalogue:
... print item.rpartition(',')[0]
...
YELLOW,SMALL,STRETCH,ADULT
YELLOW,SMALL,STRETCH,ADULT
YELLOW,SMALL,STRETCH,ADULT
I haven't compared its performance against the previous two answers.
python -m timeit -n 20000000 '"YELLOW,SMALL,STRETCH,ADULT,T21fdsfdsfs".rpartition(",")[0]' gives 0.301 usec per loop and python -m timeit -v -n 20000000 '"YELLOW,SMALL,STRETCH,ADULT,T21fdsfdsfs".rsplit(",", 1)[0]' gives 0.489 usec per loop. I'm using python-2.7-8.fc14.1.x86_64 on Core 2 Duo E6400.
python -m timeit -v -n 20000000 '",".join("YELLOW,SMALL,STRETCH,ADULT,T21fdsfdsfs".split(",")[:4])' yields: 1.19 usec per loop.If you refer to string elements, you can utilize
str.rsplit() to separate each string, setting maxsplit to 1.
str.rsplit([sep[, maxsplit]])Return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done, the rightmost ones. If sep is not specified or None, any whitespace string is a separator. Except for splitting from the right, rsplit() behaves like split() which is described in detail below.
>>> lst = "YELLOW,SMALL,STRETCH,ADULT,T"
>>> lst.rsplit(',',1)[0]
'YELLOW,SMALL,STRETCH,ADULT'
>>>
