What is async in Python?

Question

I've read about new Python "keywords" async and await. However they are neither really keywords nor reserved in a namespace.

>>> import keyword
>>> keyword.iskeyword("async")
False
>>> async
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'async' is not defined

In the example I would expect True and SyntaxError for a keyword.

So, what exactly is async in Python? How it works?

async only applies in Python 3.5. Is that the version you are using? — Akshat Mahajan
– Akshat Mahajan, Commented Apr 7, 2017 at 21:52
async and await aren't "real" keywords yet, but they will be in Python 3.7. — vaultah
– vaultah, Commented Apr 7, 2017 at 21:53
@Thyrst': If you look at the reference grammar for Python 3.6, you'll see that async and await have no independent identity when defined without a function definition next to it. So they aren't keywords, but the compiler will recognise them if you put a lambda function next to it. — Akshat Mahajan
– Akshat Mahajan, Commented Apr 7, 2017 at 21:56

user2357112 · Accepted Answer · 2018-07-27 01:24:53Z

10

For backward compatibility purposes, in Python 3.5 and 3.6, async and await are parsed through an ugly tokenizer hack. Inside an async def function definition, or for an async directly before a def, the tokenizer replaces NAME tokens for async and await with ASYNC and AWAIT tokens; in other contexts, the tokenizer emits regular NAME tokens for async and await, treating them as identifiers.

You can see the code that handles it in Parser/tokenizer.c, and you can find the backward compatibility plan in PEP 492, the PEP that introduced async and await syntax.

edited Jul 27, 2018 at 1:24

answered Apr 7, 2017 at 21:58

user2357112

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